X^2+15x-9450=0

Solution for X^2+15x-9450=0 equation:

X^2+15X-9450=0

a = 1; b = 15; c = -9450;
Δ = b2-4ac
Δ = 152-4·1·(-9450)
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38025}=195$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-195}{2*1}=\frac{-210}{2}
=-105
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+195}{2*1}=\frac{180}{2}
=90
$